A balloon is inflated with 2.42 L of helium at a temperature of 27 degrees celsius. Later, the volume of the balloon has changed to 2.37 L at a temperature of 19 degrees celsius and a pressure of 99.7 kPa. What was the pressure when the balloon was inflated?

Explanation:

Hello,

In this case, we use the combined law of gases which helps us to understand the changing pressure-volume-temperature behavior as shown below:

In this case, we are asked to compute the initial pressure before the ballon inflation, considering we must use absolute temperature units, therefore:

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Pressure when the balloon was inflated is 100kPa

Explanation:

It is possible to find the pressure of a gas in a state using combined gas law:

P₁V₁/T₁ = P₂V₂/T₂

Where P is pressure, V is volume and T is absolute temperature (°C+273.15) of 1, initial state, and 2, final state.

Replacing:

P₁2.42L/(27°C+273.15) = 99.7kPa*2.37L/(19°C+273.15)

P₁ = 100kPa

Pressure when the balloon was inflated is 100kPa

geosphere and hydrosphere.

this is because the geosphere has to do with geological events, while the hydrosphere controls all water on earth.