33.23 grams of a thin sheet of iron is completely oxidized in 7 days. How would you express the rate of conversion of the silver?

.0440 moles/day
.183 moles/hour
.0440 moles/week
.308 moles/day

A. 0.0440 moles/day

Explanation:

First, let's figure out how many moles 33.23 grams of silver is. We do this by dividing the number of grams by the molar mass of silver, which is 107.87 g/mol:

33.23 g Ag ÷ 107.87 g/mol = 0.3081 mol Ag

Now, let's divide this by 7 to get the rate per day:

0.3081 mol Ag ÷ 7 days = 0.0440 mol/day

Thus, the answer is A.

the answer would be a

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