Chemistry, 27.05.2020 04:58, phsycotic121
What is the concentration of the silver ion in silver chromate, Ag₂CrO₄, if its solubility product constant (Kₛₚ) is 1.2 x 10⁻¹². Hint: write the equation first! *
2 points
1.4 x 10⁻⁵
1.1 x 10⁻⁹
1.6 x 10⁻¹²
2.4 x 10⁻¹²
Answers: 1
![[Ag^+]=1.3x10^{-4}M](/tpl/images/0666/7571/0a833.png)
![Ksp=[Ag]^2[CrO_4^{-2}]](/tpl/images/0666/7571/75fed.png)
due to the dissolution of silver chromate, we obtain:
![x=\sqrt[3]{\frac{1.2x10^{-12}}{2^2} } = 6.7x10^{-5}M](/tpl/images/0666/7571/1e8f3.png)
![[Ag^+]=2x=2*6.7x10^{-5}M=1.3x10^{-4}M](/tpl/images/0666/7571/1be44.png)
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What is the concentration of the silver ion in silver chromate, Ag₂CrO₄, if its solubility product c...
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