How much heat is lost when a 692 g piece of aluminum cool from 176°C to 85°C? The specific heat of aluminum is 0.125 cal/g°C.

Heat loss is -7871.5J

Explanation:

Mass = 692g

Initial temperature (T1) = 176°C

Final temperature (T2) = 85°C

Specific heat capacity of Al = 0.125J/g°C

Heat energy = ?

Q = mc∇t

Q = heat energy

M = mass of substance

C = specific heat capacity of substance

∇t = change in temperature of substance = T2 - T1

Q = mc∇t

Q = 692 × 0.125 × (85 - 176)

Q = 86.5 × -91

Q = -7871.5J

The heat loss is -7871.5J or -7.87kJ

the law of conservation of mass states that in a chemical reaction, the total mass of reactants is equal to the total mass of products. because atoms are only rearranged in a chemical reaction, there must be the same number of sodium atoms and chlorine atoms in both the reactants and products