In an experiment, 8.67 ml of a .87M acetic acid solution was titrated with .250 sodium hydroxide. Predict by calculating the volume of base that should be used?

We need 30.2 mL of NaOH

Explanation:

Step 1: Data given

Volume of acetic acid solution = 8.67 mL = 0.00867 L

Concentration of acetic acid solution = 0.87 M

Concentration of sodium hydroxide = 0.250 M

Step 2: The balanced equation

CH3COOH + NaOH → CH3COONa+ + H2O

Step 3: Calculate the volume of sodium hydroxide

b*Ca*Va = a*Cb*Vb

⇒with b = the coefficient of NaOH = 1

⇒with Ca = the concentration of CH3COOH = 0.87 M

⇒with Va = the volume of CH3COOH = 0.00867 L

⇒with a = the coefficient of CH3COOH = 1

⇒with Cb = the concentration of NaOH = 0.250 M

⇒with Vb = the volume of NaOH = TO BE DETERMINED

1 * 0.87 M * 0.00867 L = 1 *0.250 M * Vb

Vb = (0.87 M * 0.00867 L) / 0.250 M

Vb = 0.0302 L = 30.2 mL

We need 30.2 mL of NaOH

question: ray weighs 100 kilograms, his wrestling partner, bobby, weighs 50 kilograms. if ray moves at 4 m s , how fast will bobby have to run at him to apply an equal amount of kinetic energy?

answer: 8 m/s he needs to run twice as fast to keep up so he has some work to do

explanation:   if the mass has units of kilograms and the velocity of meters per second, the kinetic energy has units of kilograms-meters squared per second squared.

question answered by

(jacemorris04)

under a microscope, cancer cells may look very different from normal cells. they often have different sizes and some may be larger than normal while others are smaller. cancer cells are often abnormally shaped and the control centre of the cell (the nucleus) may have an abnormal appearance.

i think? ?