A gas has a pressure of 75 KPa and a volume of 33 Liters. What's the new
pressure if the volume is changed to 55 Liters?

45kPa

Explanation:

P1 = 75kPa = 75,000Pa

V1 = 33L

V2 = 55L

P2 = ?

To solve this question, we'll have to apply Boyle's law which states that the volume of a fixed mass of gas is inversely proportional to its pressure provided its temperature remains constant

Mathematically,

V = k / P, k = PV

P1×V1 = P2×V2 = P3×V3==Pn×Vn

P1 × V1 = P2 × V2

P2 = (P1 × V1) / V2

P2 = (75000 × 33) / 55

P2 = 45000Pa

P2 = 45kPa

The final pressure of the gas is 45kPa

your answer would be a. 12.5 kg

explanation:

metals have excess of electrons whereas non-metals have deficiency of electrons. thus, in order to gain stability metals easily donate their electrons to the non-metals.

for example, electronic configuration of sodium is and electronic configuration of phosphorous is .

when a phosphorous atom and sodium atom combine together then sodium will donate is extra one electron to the phosphorous atom. as a result there will be formation of ionic bond between sodium and phosphorous.

the reaction will be as follows.

there, are three sodium sodium atoms and each of them will donate its one extra electron to phosphorous atom. thus, the sub-shell of phosphorous gets completely filled.  

thus, we can conclude that electrons are transferred from atoms of sodium to atoms of phosphorous. this transfer makes the sodium atoms donate one electron and the phosphorous atoms to gain one electron. as a result, the sodium and phosphorus atoms strongly attract each other.