A first order reaction has rate constants of 4.6 x 10-2 s-1 and 8.1 x 10-2 s-1 at 0ºC and 20ºC, respectively. What is the value for the activation energy?
A.
0.566 J/mol
B.
2.5 x 10-4 J/mol
C.
2260 J/mol
D.
18,800 J/mol
E.
1.76 J/mol

D.  18,800 J/mol

Explanation:

We need to use the Arrhenius equation to solve for this problem:

, where k is the rate constant, A is the frequency factor, is the activation energy, R is the gas constant, and T is the temperature in Kelvins.

We want to find the value of , so let's plug some of the information we have into the equation. The gas constant we can use here is 8.31 J/mol-K.

At 0°C, which is 0 + 273 = 273 Kelvins, the rate constant k is . So:

At 20°C, which is 20 + 273 = 293 Kelvins, the rate constant k is . So:

We now have two equations and two variables to solve for. We just want to find Ea, so let's write the first equation for A in terms of Ea:

Plug this in for A in the second equation:

After some troublesome manipulation, the answer should come down to be approximately:

Ea = 18,800 J/mol

The answer is thus D.

a chemical reaction

explanation:

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