50 points !! for this question
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Here's what I get  

Explanation:

1. At 0 mL HCl

pOH = -log[OH⁻] = -log(0.125) = 0.90

pH = 14.00 - pOH = 14.00 - 0.90 = 13.10

2. At 10 mL HCl

Initial moles NaOH = 25.0 mL × 0.125 mmol/mL = 3.125 mmol NaOH

Moles HCl added = 10 mmol × 0.0625 mmol/L = 0.625 mmol HCl

Moles NaOH remaining = (3.125 - 0.625) mmol = 2.50 mmol NaOH

Total volume = (25.0 + 10) mL= 35.0 mL

[OH⁻] =2.50/35 = 0.071 43 mol·L⁻¹

pOH = 1.15

pH = 12.85

3. At 50 mL HCl

Initial moles NaOH = 3.125 mmol NaOH

Moles HCl added =3.125 mmol HCl

Moles NaOH remaining = 0

We are at the equivalence point.

pH = 7.00

4. At 70 mL HCl

Initial moles NaOH = 3.125 mmol NaOH

Moles HCl added =4.375 mmol HCl

Excess moles HCl = 1.25 mmol HCl

Total volume = 95 mL

[H⁺] = 0.013 16 mol·L⁻¹

pH = 1.88

5. Table

7. Titration Curve

See below.

in chemistry, adhesion and cohesion are attractive forces that exist between molecules. they hold the molecules together from each other. they are different in that adhesive force exists between molecules of different substance while cohesive force happens between molecules of same substance.

adhesion between water and glass causes water molecules at the edge of water and glass interface to climb up the wall in a narrow glass tube. this is called capillary action. cohesion is what gives glass its shape and causes water to form a droplet.