Using the provided table and the equation below, determine the heat of formation for CuBr₂.
CuCl₂ (s) + Br₂(l) → CuBr₂ (s) + Cl₂ (g) ∆H° = 64.1 kJ/mol
Table:
CuCl2 (s) = -205.9
Br2 (I) = 0
Cl2 (g) = 0

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