Given the balanced equation representing a redox reaction:

2Al + 3Cu2+ → 2Al3+ + 3Cu

Which statement is true about this reaction?

The given question is incomplete, the complete question is:

Given the balanced equation representing a redox reaction:

2Al + 3Cu2+ --> 2Al3+ + 3Cu

Which statement is true about this reaction?

(1) Each Al loses 2e- and each Cu2+ gains 3e-

(2) Each Al loses 3e- and each Cu2+ gains 2e-

(3) Each Al3+ gains 2e- and each Cu loses 3e-

(4) Each Al3+ gains 3e- and each Cu loses 2e-

The correct answer is option 2, that is, in the given reaction each of Al loses three electrons and each of the Cu^2+ ion acquires two electrons.

Explanation:

To understand the concept, let us suppose that when an atom A loses an electron, it turns into an atom A^1+, and becomes A^2+ when it loses two electrons. On the other hand, when an atom A gains an electron, it turns into A^1- and becomes A^2- when it acquires two electrons.  

Therefore, in the given case, 2Al + 3Cu^2+ --> 2Al^3+ + 3Cu, each of the Al atom turns into Al^3+ when it loses three electrons, and when each of the Cu^2+ ions acquires two electrons, it turns into Cu (Cu^2+ ^2- = Cu).  

the correct option is c.

isotopes refers to different forms of the same element with the same atomic number but different mass number as a result of difference in their neutron numbers. isotopes have different relative atomic mass but share the same chemical properties.

answer: i have one answer

acids are substances that ionize (break off) in an aqueous solution to produce hydrogen (h+) ions

explanation:

hope this and sorry i could only come up with one answer!