Given the reaction:

2 NaOH + H2SO4 Na2SO4 + 2 H2O

How many milliliters of 1 M NaOH are needed to exactly neutralize 100 milliliters of 1 M H2SO4?

a

50 ml

b

100 ml

c

200 ml

d

400 ml

Option C. 200mL

Explanation:

We'll begin by writing the balanced equation for the reaction. This is illustrated below:

2NaOH + H2SO4 –> Na2SO4 + 2H2O

From the balanced equation above,

The mole ratio of the acid (nA) = 1

The mole ratio of the base (nB) = 2

The following data were obtained from the question:

Molarity of the base (Mb) = 1M

Volume of the base (Vb) =..?

Molarity of the acid (Ma) = 1M

Volume of the acid (Va) = 100mL

The volume of the base needed can be obtained as follow:

MaVa/MbVb = nA/nB

1 x 100 /1 xVb = 1/2

Cross multiply to express in linear form

Vb = 1 x 100 x 2

Vb = 200mL

Therefore, the volume of the base needed for the reaction is 200mL

if you mean hydrogen and oxygen then water is the product

they it depends on if one believes about radioactivity, they make a geiger counter beep but maybe it was going to beep anyway electronics do wierd things all the time or it was programmed to beep near certain metals.