How many moles of NaCl are present in 530 ml of a 1.52m NaCl solution

805.6 moles

Explanation:

Molarity = 1.52mL

Volume = 530mL

1.52 moles is present in 1mL,

1mL = 0.001L

1.52 moles = 0.001L

X moles = 0.53L

X = (1.52 × 0.53) / 0.001

X = 805.6moles

805.6moles is present in 530mL or 0.52L

chemical digestion occurs in the stomach were hcl and pepsin forms chyme, the mouth in which salivary amylase breaks down starch to form bolus, and the small intestine specifically the duodenum.