What is the molarity if 2.00 liters containing 49.0 grams of sodium carbonate [Na2CO3)?
(Molar mass of Na is 22.99 g/mol, C is 12.01 g/mol and O is 16.00 g/mol.)

The molarity of solution is 0.231 M

Explanation:

Molarity of a solution is defined as the number of moles of solute dissolved per liter of the solution.

where,

n = moles of solute

= volume of solution in L

Molar mass of =

moles of =

Now put all the given values in the formula of molality, we get

Therefore, the molarity of solution is 0.231 M

a. the law of proportion states the combination of 2 atoms in a specific ratio to produce multiple compounds such as the given statement of question ‘1st compound contains 88.8 % cu ’ indicates 88.8 g of cu is present along with 11.2 g oxygen in 100 g of compound whereas the statement ‘2st compound contains 79.9 % cu ’ indicates 79.9 g of cu is present along with 20.1 g oxygen in 100 g of compound

1st compound contains 88.8 g cu

for cu

m = 63 g /mol

atomic % = 88.8 /63 = 1.42

for o

m = 16 g /mol

atomic % = 11.2 /16 = 0.7

b. the emperical formula of 1st compound is

cu1.4o0.7

cu2o