What is the temperature of an ideal gas if 2.50
moles of the gas occupy a 3.00 liter container
at a pressure of 2500. kPa? Record your answer
to the nearest Kelvin.
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The temperature of an ideal gas is 360 K

Explanation:

According to ideal gas equation:

P = pressure of gas = 2500 kPa = 24.67 atm   (1kPa= 0.0098atm)

V = Volume of gas = 3.00 L

n = number of moles = 2.50 mol

R = gas constant =

T = temperature = ?

Thus the temperature of an ideal gas if 2.50 moles of the gas occupy a 3.00 liter container is 360 K

in the given question, the partial pressure is calculated by using the ideal gas equation, that is, pv = nrt

here, p is pressure, v is volume = 25 l, n is number of moles = 0.0104 moles, r is gas constant = -0.0821 l.atm / mol.k

t is temperature = 273 k

p = nrt / v

p = (0.0104 mol × 0.0821 l.atm / mol.k × 273 k) / 25 l

= 0.0093 atm

warm front forms when a moist, warm air mass slides up and over a cold air mass. as the warm air mass rises, it condenses into a broad area of clouds. a warm front brings gentle rain or light snow, followed by warmer, milder weather.

hope i !