If the acetylene tank contains 37.0 mil of C2H2 and the oxygen tank contains 81.0 mol of O2, what is the limiting reactant for this reaction
2C2H2(l)+502(g) 4CO2(g)+2H2O(g)

Explanation:

2C₂H₂(l)  +  50₂(g) =   4CO₂(g)  +  2H₂O(g)

2 mol          5 mol

2 mol of C₂H₂ reacts with 5 mol of O₂

37 mol of C₂H₂  will require 5/2 x 37 mol of O₂

= 92.5 mol of O₂

But oxygen available is only 81 mol so formation of product will be controlled by oxygen available . Hence oxygen is the limiting factor.

2b2t

explanation:

2b2t

a. the law of proportion states the combination of 2 atoms in a specific ratio to produce multiple compounds such as the given statement of question ‘1st compound contains 88.8 % cu ’ indicates 88.8 g of cu is present along with 11.2 g oxygen in 100 g of compound whereas the statement ‘2st compound contains 79.9 % cu ’ indicates 79.9 g of cu is present along with 20.1 g oxygen in 100 g of compound

1st compound contains 88.8 g cu

for cu

m = 63 g /mol

atomic % = 88.8 /63 = 1.42

for o

m = 16 g /mol

atomic % = 11.2 /16 = 0.7

b. the emperical formula of 1st compound is

cu1.4o0.7

cu2o