What is the concentration of each ion in 0.250 M Na2SO4?

The concentration of is 0.500 M and is 0.250 M in 0.250 M

Explanation:

The dissociation of is given as:

As 1 mole of gives  = 2 moles of

0.250 moles of gives = moles of

As 1 mole of gives = 1 mole of

0.250 moles of gives = moles of

Thus the concentration of is 0.500 M and is 0.250 M in 0.250 M

the answer for sodium is 0.186

the answer for rubidium is 0.251