If the pressure exerted by a gas at 0.00 °C in a volume of 0.0010 L of 5.00 atm, how many moles of gas are present?

2.23 x 10^-4 mol

Explanation:

0°C =273 K

PV= nRT

n= PV/RT

n= (5.00 atm * 0.0010 L)/ (0.0821 * 273 K)

n= 2.23 x 10^-4

where is the following

explanation:

in chemistry, a solution’s concentration is how much of a dissolvable substance, known as a solute, is mixed with another substance, called the solvent. the standard formula is c = m/v, where c is the concentration, m is the mass of the solute dissolved, and v is the total volume