How many moles of S2F10 are contained in a pure 128-gram sample of S2F10 ?

0.504 mole

Explanation:

From the question given, the mass of S2F10 = 128g

To obtain the number of mole in 128g of S2F10, we must obtain the molar mass of S2F10.

Molar Mass of S2F10 = (32x2) + (19x10) = 64 + 190 = 254g/mol.

Now, we can obtain the number of mole as follow:

Number of mole = Mass /Molar Mass

Number of mole of S2F10 = 128/254 = 0.504 mole

hey there!

boiling point is the temperature at which the vapor pressure of the liquid equals atmospheric pressure. the vapor pressure of solvent molecules is decreased when a solute is added, so a higher temperature is required to increase the number of solvent molecules in the gas phase above the liquid.

at the freezing point, the vapor pressures of the solid and liquid are equal; a lower temperature is needed to reduce the number of solvent particles above the liquid.

hope this you

tobey