A 5 gram piece of aluminum foil at 100 degrees C is dropped into a 25 gram container of water at 20 degrees C. What is the final temperature of the aluminum.

23.30°C

Explanation:

Heat lost by Al = Heat gain by water

5× ( 100- x ) × ( 0.900) = 25× ( x-20)× ( 4.186)

(500-5x)0.900 = (25x-500)4.186

450-4.5x = 104.65x- 2093

Collecting like terms

450+2093 = 104.65x+4.5x

2543 = 109.15x

X = 2543/109.15

X = 23.298

X = 23.30°C

Final temperature of the solution is 23.3°C

Explanation:

Mass of aluminium(M1) = 5g

Initial temperature of aluminium(T1) = 100°C

Mass of water (M2) = 25°C

Initial temperature of water(T2) = 20°C

Final temperature of the solution (T3) = ?

Specific heat capacity of aluminium = 0.9J/g°C

Specific heat capacity of water = 4.184J/g°C

Heat loss by Aluminium = Heat gained by water

Q = MC∇T

Q = heat energy

M = Mass

C = specific heat capacity

∇T = change in temperature

M1C1(T1 - T3) = M2C2(T3 - T2)

5 * 0.9 *(100 - T3) = 25 * 4.184 (T3 - 20)

4.5 * (100 - T3) = 104.6 (T3 - 20)

450 - 4.5T3 = 104.6T3 - 2092

Collect liketerms

450 + 2092 = 104.6T3 + 4.5T3

2542 = 109.1T3

T3 = 2542 / 109.1

T3 = 23.299°C = 23.3°C

Final temperature of the mixture is 23.3°C

- decrease the number of plants and animals living in the water.

answers: to make sure that all of the broken pieces of tablet were added to the water, to allow for fair comparison of all three trials, with different particle sizes to avoid experimental error