Chemistry, 07.05.2020 08:57, NathanaelLopez

If I add 1.50 L of water to 250 mL of a 12.5 M NaOH solution, what will the molarity of the diluted solution be?

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answered: zachcamp5298

The molarity of the diluted solution is 1.786 M

Explanation:

Dilution is a process in which you always start with a concentrated solution to which a greater volume of solvent is added. This modifies the concentration and volume of the resulting solution, but the amount of solute used to prepare the initial solution remains the same.

In summary, in a dilution the amount of solute does not vary, but the volume of the solvent varies: when more solvent is added, the concentration of the solute decreases, as the volume (and weight) of the solution increases.

The following rule is fulfilled:

Vinicial x Cinicial = Vfinal x Cfinal

where:

Vinicial = Initial volume. Cinicial = Initial concentration Vfinal = Final volume Cfinal = Final concentration

In this case:

Vinicial= 250 mL= 0.25 L (Being 1 L=1000 mL)Cinicial= 12.5 MVfinal= 1.5 L+ 0.25 L=1.75 LCfinal= ?

Replacing:

0.25 L* 12.5 M= 1.75 L* Cfinal

Solving:

$Cfinal=\frac{0.25 L* 12.5 M}{1.75 L}$

Cfinal= 1.786 M

The molarity of the diluted solution is 1.786 M

answered: Guest

Read the sentences below in 1962, i tried to enroll as the first black student at the university of mississippi. the governor of mississippi blocked my entrance which best describes the verbs used in the sentences? o they are past tense verbs, which are often used in narrative essays o they are past tense verbs, which are not often used in narrative essays. o they are future tense verbs, which are often used in narrative essays o they are future tense verbs, which are not often used in narrative essays.

answered: Guest

the correct answer is b. a strong acid completely dissociates to its ions when dissolved in water. $hbr$ completely dissociates to $h^+$ and $br-$ ions. a is incorrect because $h_2s$ does not fully ionize to $h^+$ and $hs^-$ ions and some remain as the compound $h_2s$ . c and d are incorrect because, $li_2o$ and $libr$ do not fall into the category of bronsted lowry acids. a bronsted lowry acid is a proton donor and since both molecules do not have a proton to donate they are not bronsted lowry acids. likewise, if we use the lewis acid definition, they cannot be acids. a lewis acid is an electron pair acceptor. both $li_2o$ and $libr$ have a complete octet so can not accept any electrons which disqualifies them as acids.

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If I add 1.50 L of water to 250 mL of a 12.5 M NaOH solution, what will the molarity of the diluted...