What additional information is needed to solve this problem: If a sample of a gas 12.0 o C and 1.06 atm pressure is moved to a 2.30 L container at 24.9 0 C, what is the final pressure of the gas?

The additional information required to solve this problem is the initial volume.

the final pressure P₂ of the gas is 1.108 atm

Explanation:

Given that :

A sample of gas at initial temperature = (12+273)K = 285 K

Pressure (P₁) = 1.06 atm

Initial Volume (V₁) = unknown ???

Final Volume (V₂) = 2.30 L

final temperature  = (24.9 +273)K = 297.9 K

Find the final Pressure (P₂)

The relation between: Pressure, Volume and Temperature can be gotten from the ideal gas equation :

PV = nRT

The Ideal Gas Equation is also reduced to the General Gas Law or the combined Gas Law by assuming that n= 1 .

From ; PV = nRT

∴

The additional information required to solve this problem is the initial volume.

This expression is a combination of Boyle's Law and Charles Law. From the combined Gas Law , it can be deduced that at constant volume, the pressure of a given mass(mole) of gas varies directly with absolute temperature.

∴  if n & Volume (V) are constant .

P₂ = 1.108 atm

Thus, the final pressure P₂ of the gas is 1.108 atm

every chemical equation adheres to the law of conservation of mass, which states that matter cannot be created or destroyed. therefore, there must be the same number of atoms of each element on each side of a chemical equation.