Chemistry, 07.05.2020 03:07, Packergood

The combustion of isopropanol, i. e. rubbing alcohol, releases 1,830 kJ/m
Given that the molecular weight of isopropanol is 60.096 g/mol, calculat
147 kJ
Calc
1,370 kJ
Formulas
2,160 kJ
4,950 kJ
Highlight

Answers: 1

Show answers

Other questions on the subject: Chemistry

Chemistry, 21.06.2019 17:10, PSBSolarYT

For which one of the following reactions is the value of δh° rxn equal to δh° f for the product? a. 2 h2 (g) + o2 (g) → 2 h2o (l) b. n2 (g) + o2 (g) → 2 no (g) c. 2 h2 (g) + o2 (g) → 2 h2o (g) d. h2o (l) + 1/2 o2 (g) → h2o2 (l) e. none of the above

Answers: 1

continue

Chemistry, 22.06.2019 20:10, sarahalexa19

Suppose you mix one mole of sulfuric acid (h2so4) with 1 mole of sodium hydroxide(naoh). why does the ph of the solution remain below 7? ( explain so i can get better understanding! )

Answers: 2

continue

Chemistry, 23.06.2019 02:00, ItzAquaZ1449

Alice did an experiment to find the relationship between the angle at which a ray of light strikes a mirror and the angle at which the mirror reflects the light. she placed a ray box in front of a mirror. she changed the angle at which the light from the ray box struck the mirror and noted the corresponding angle at which the mirror reflected the light. which of the following is the dependent variable in this experiment? the mirror used to reflect the light the ray box used as the source of light angle at which the light from the ray box strikes the mirror angle at which the mirror reflects the light from the ray box

Answers: 2

continue

Chemistry, 23.06.2019 15:30, camiee13dvivvj

You can smell perfume because of which change of state

Answers: 1

continue

Do you know the correct answer?

The combustion of isopropanol, i. e. rubbing alcohol, releases 1,830 kJ/m
Given that the molec...