How many grams of HF are needed to react with 3.0 moles of Sn?*
10 points
→ SnF2 + H2
Sn + 2 HF
O 309
O 609
120g
2409

120 grams of HF are needed to react with 3.0 moles of Sn

Explanation:

The balanced chemical equation is :

According to stoichiometry:

1 mole of reacts with 2 moles of HF

Thus 3.0 moles of Sn will react = moles of HF

Mass of

Thus 120 grams of HF are needed to react with 3.0 moles of Sn

the answer is alpha particles hope i you

a: 45.9 meters

b: 4.29 seconds

step-by-step explanation:

a: h(t)=1/2(-9.8)(3)^2+0(3)+90

h(t)=-4.9(3)^2+90

h(t)=-44.1+90

h(t)=45.9 meters

b: 0=1/2(-9.8)(t^2)+0t+90

0=-4.9t^2+90

-90=-4.9t^2

18.37=t^2

t=4.29 seconds

in the second question, the numbers aren't exact, but they're a close approximation.