A chemistry student needs 125 mL of 0.150 NaOH solution for her experiment but the only solution available in laboratory is 3.02 M describe how student could prepare the solution she needs.

The student needs to measure out 6.21mL of the stock solution and dilute it to 125mL with water.

Explanation:

To obtain the desired solution, the student need to determine how much of the stock solution she will need.

Now, let us calculate the volume of the stock solution needed.

Data obtained from the question include:

Molarity of the stock solution (M1) = 3.02 M

Volume of the stock solution needed (V1) =...?

Molarity of the diluted solution (M2) = 0.150 M

Volume of the diluted solution (V2) = 125mL

Using the dilution formula, the volume of the stock solution needed can be obtained as follow:

M1V1 = M2V2

3.02 x V2 = 0.15 x 125

Divide both side by 3.02

V2 = (0.15 x 125)/3.02

V2 = 6.21 mL.

Therefore, the student needs to measure out 6.21mL of the stock solution and dilute it to 125mL with water.

atomic number of carbon is 6

electronic configuration of carbon is 1s²2s²2p²

orbital diagram of c is as shown here in the image.

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