While rowing in a race, John pulls the handle of an oar 0.80 m on each
stroke. If the oar has a MA of 1.5, how far does the blade of the oar move
through the water on each stroke?

According to the question,

Input distance,

Mechanical advantage,

The output distance is:

=

By putting the values,

=

=

Thus the above answer is right.

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Stroke D (Output Distance) = 0.533 meter (Approx)

Explanation:

Given:

Stroke D (Input Distance) = 0.80 meter

Mechanical advantage (MA) = 1.5

Find:

Stroke D (Output Distance) = ?

Computation of Stroke D (Output Distance) :

⇒ Stroke D (Output Distance) = Stroke D (Input Distance) / Mechanical advantage (MA)

⇒Stroke D (Output Distance) = 0.80 meter / 1.5

⇒ Stroke D (Output Distance) = 0.533 meter (Approx)

percent abundance for cu-63 can be shown as:

63 x + 65 (1-x) = 62.9296

65 - 62.9296 = 2 x

x = 1.035

thus, percent abundance for cu-63 is 1.035

percent abundance for cu-65 can be shown as:

63 x + 65 (1-x) = 64.9278

65 - 64.9278 = 2 x

x = 0.0361

thus, percent abundance for cu-63 is 0.0361

the mass spectrum of cu-63 showing the intense peak as, this isotope is found in nature more abundantly around 92.38 % in comparison to cu-65 which is found 62.58 % naturally