When 100 cm3 of a saturated solution of KClO3 at 40°C is evaporated, 14.0g of the salt is recovered. What is the solubility of KClO3 at 40°C

Explanation:

kclo3- 39+35.5+16*3=122.5

molar mass = 122.5

mass = 14.0g

volume= 100cm3

solubility in mol/dm3 or molarity = ?

but we know that

no of moles = solubility in mol/dm3×vol in cm3

1000

no of moles = mass

molar mass

mass\molar mass= solubility in mol/dm3 *vol in cm3/ 1000

14.0/122.5=x * 100/1000

solubility =0.875 mol/dm3

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