What would be the temperature of 0.6 moles of fluorine that occupy 15 L at 2,300 mmHg?

The temperature of 0.6 moles of fluorine that occupy 15 L at 2,300 mmHg is 920 K

Explanation:

According to ideal gas equation:

P = pressure of gas = 2300 mm Hg = 3.02 atm  (760mmHg=1atm)

V = Volume of gas = 15 L

n = number of moles = 0.6

R = gas constant =

T =temperature = ?

Thus the temperature of 0.6 moles of fluorine that occupy 15 L at 2,300 mmHg is 920 K

in the analysis of systems that involve fluid flow, we frequently encounter the combination of properties u and pv.