The fuel used in many disposable lighters is liquid butane, C4H10
C
4
H
10
. Butane has a molecular weight of 58.1 grams in one mole. How many carbon atoms are in 3.50 g
g
of butane?

1.45 *10^23 atoms C

Explanation:

3.50 g butane * 1 mol butane/58.1 g butane =0.06024 mol butane

in 1 mol C4H10           4 mol C

in 0.06024 mol C4H10 4*0.6024 = 0.241 mol C

0.241 mol C * 6.02*10^23 atoms C/1 mol C = 1.45 *10^23 atoms C

answer is: c. the experiment shows that the red substance experienced a chemical change.

this is chemical change (chemical reaction), because two new substances are formed (metalig liquid and gas), the atoms are rearranged and the reaction is followed by an energy change.

this is example of chemical decomposition.

chemical decomposition (analysis) is the separation of a single chemical compound into its two or more elemental parts or to simpler compounds.  

chemical decomposition is opposite of chemical synthesis.