How many moles of water are present in 15.00 ml of water
that has a density of 0.9956 g/ ml.
MW for Hydrogen 1.00 g/ 1 mole; MW for Oxygen 16.00 g/ 1 mole

Answer : The moles of water present in solution are, 0.8297 moles.

Explanation :

First we have to calculate the mass of water.

Now we have to calculate the moles of water.

Molar mass of water = (2 × Molecular weight of hydrogen) + Molecular weight of oxygen

Molar mass of water = (2 × 1.00g/mol) + 16.00 g/mol

Molar mass of water = 18.00 g/mol

Therefore, the moles of water present in solution are, 0.8297 moles.

the equation that correctly represent the reaction for formation of ammonia is

n2+ 3h2 → 2nh3 (answer d)

1 mole of nitrogen gas (n2) react with 3 moles of hydrogen gas (h2) to form 2 moles of ammonia ( nh3). this is in a process known as haber process were iron is used as a catalyst and reaction take place that a higher temperature and pressure. the process is exothermic hence energy is released.