A closed, adjustable cylinder containing 6.2 moles of oxygen gas has a volume of 4.3 liters and a pressure of 3.8 atmospheres. If the cylinder's volume is changed so that it is 15.5 liters, what is the new pressure of the gas? Round your answer to the nearest 0.01 atm.

The new pressure is 1.05 atm

Explanation:

Step 1: Data given

Number of moles oxygen gas = 6.2 moles

Volume of the cylinder = 4.3 L

Pressure of the gas = 3.8 atm

The volume changed to 15.5 L

Step 2: Calculate the new pressure

P1*V1 = P2*V2

⇒with P1 = the initial pressure of the gas = 3.8 atm

⇒with V1 = the initial volume = 4.3 L

⇒with V2 = the increased volume = 15.5 L

⇒with P2 = the new pressure = TO BE DETERMINED

3.8 atm * 4.3 L = 15.5 L * P2

P2 = (3.8 atm *4.3 L) / 15.5 L

P2 = 1.05 atm

The new pressure is 1.05 atm

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2b2t

explanation:

2b2t