The unheated gas in the above system has a volume of 20.0 L at a temperature of 25.0 °C and a pressure of 1.00 atm. The gas is heated to a temperature of 100.0 °C while the volume remains constant. What is the pressure of the heated gas?

The pressure of the heated gas is 1.25atm

Explanation:

Using pressure law equation;

P1/T1 = P2/T2

P2 = P1T2 / T1

P1 = 1atm

T2 = 100 C = 100 + 273K = 373K

T1 = 25.0 C = 25 +273K = 298K

Solving for P2 we equate the values and we get;

P2 = P1T2 / T1

P2 = 1 * 373 / 298

P2 = 1.25 atm.

The pressure of the heated gas is 1.25 atm.

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