A compound (C7H14O) has a strong peak in it’s IR spectrum at 1710 cm-1. It’s 1H NMR spectrum consists of only three singlets in the ratio 9:3:2 at δ = 1.0, 2.1, 2.3 ppm respectively. Identify the compound.

Explanation:

The IR spectrum at 1710 cm⁻¹ illustrates how stretched the carbonyl group is:

The name of the  carbonyl compound is: 4,4-dimethyl-2-pentanone.

For the identification of the compound, check the attached word document below.

explanation:

let the different atoms be x and y. each with four protons and same mass will be represented as follows.

mass number is number of protons + number of neutrons.

            and  

since, it is given that one has a negative charge while the other is neutral. therefore, there will be increase in number of protons and the atom will be represented as follows.

according to periodic table, mass number of beryllium is 9 and it has atomic number 4 so, the atoms will be and .  

the protons and neutrons will be located inside the nucleus whereas the electrons will be revolving around the nucleus.