Calculate the number of grams of calcium perchlorate (Ca(ClO4)2) in 6.37 x 1018 formula units of calcium perchlorate?

2.53x10⁻³g of Ca(ClO₄)₂

Explanation:

It is possible to convert formula units to moles using Avogadro's number and then, these moles to grams with molar mass, thus:

6.37x10¹⁸F.U. ₓ (1mole / 6.022x10²³F.U.) = 1.06x10⁻⁵ moles of Ca(ClO₄)₂

Molar mass of Ca(ClO₄)₂ is:

1 Ca = 1×40.08g/mol = 40.08g/mol

2 Cl = 2×35.45g/mol = 70.90g/mol

8 O = 8×16g/mol = 128g/mol

Molar mass:

40.08g/mol + 70.90g/mol + 128g/mol = 238.98g/mol

Thus, mass of 1.06x10⁻⁵ moles of Ca(ClO₄)₂ is:

1.06x10⁻⁵ moles of Ca(ClO₄)₂ × (238.98g/mol) = 2.53x10⁻³g of Ca(ClO₄)₂

in 1783 cavendish was working with his hydrogen gas and found that when he burned it and condensed the vapor it was water. this was very significant since it disproved the greek theory of elements completely since water was not a simple substance but the product of two gases. it was lavoisier who hearing of the experiment gave cavendish's gas the name hydrogen ("water-producer") and added that hydrogen burned by combining with oxygen and that water was a hydrogen-oxygen combination.

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