Methane burns in the presence of oxygen to produce carbon dioxide and water in the following reaction:

CH4 (s) + 2 O2 (g) --> CO2 (g) + 2 H2O (l)

What mass of methane (in grams) will require 35.15 L of oxygen to fully react? The pressure is 2.35 atm and the temperature is 15 °C. (R = 0.0821 L atm/mol K)

The mass of methane that will require 35.15 L of oxygen to fully react is 27.04 grams

Explanation:

Here we have 2 moles of oxygen gas combining with 1 mole of methane gas

At 2.35 atm  and 15 °C, the volume of oxygen is 35.15 L

Number of moles, n of oxygen is given by the following relation;

Therefore

Therefore, since 2 moles of oxygen gas combining with 1 mole of methane the number of moles of methane combining with 3.375 moles of oxygen = 3.375/2 moles or 1.69 moles of methane

Molar mass of methane = 16.04 g/mol

Therefore, mass of 1.69 moles of methane = 16.04 g/mol × 1.69 mole = 27.064 g

Which means that the mass of methane that will require 35.15 L of oxygen to fully react = 27.04 grams.

because u need two or more forms of the same element that contain equal numbers of protons but different numbers of neutrons in their nuclei to form isotopes.

so since they all have the same shape? i mean maybe because m& m and reeses are both chocolates