Answers: 2
![pH=-\log[H^+]](/tpl/images/0643/0989/cf945.png)
![pOH=-\log[OH^-]](/tpl/images/0643/0989/fe336.png)
![7=-\log[H^+]](/tpl/images/0643/0989/1fb8e.png)
![[H^+]=10^{-7}M](/tpl/images/0643/0989/0ed7f.png)
![5=-\log[H^+]](/tpl/images/0643/0989/54e2a.png)
![[H^+]=10^{-5}M](/tpl/images/0643/0989/34493.png)
![\frac{[H^+]_{pH=5}}{[H^+]_{pH=7}}=\frac{10^{-5}}{10^{-7}}\\\\\frac{[H^+]_{pH=5}}{[H^+]_{pH=7}}=10^2](/tpl/images/0643/0989/c09c8.png)
![[H^+]_{pH=5}=100\times [H^+]_{pH=7}](/tpl/images/0643/0989/ec551.png)
![7=-\log[OH^-]](/tpl/images/0643/0989/783d7.png)
![[OH^-]=10^{-7}M](/tpl/images/0643/0989/889ca.png)
![9=-\log[OH^-]](/tpl/images/0643/0989/7e7a8.png)
![[OH^-]=10^{-9}M](/tpl/images/0643/0989/f7c96.png)
![\frac{[OH^-]_{pH=7}}{[OH^-]_{pH=5}}=\frac{10^{-7}}{10^{-9}}\\\\\frac{[OH^-]_{pH=7}}{[OH^-]_{pH=5}}=10^2](/tpl/images/0643/0989/17ac9.png)
![[OH^-]_{pH=7}=100\times [OH^-]_{pH=5}](/tpl/images/0643/0989/65bd7.png)
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