Liquefied natural gas (LNG) is transported in very large tankers, stored as liquid in equilibrium with its vapor at approximately atmospheric pressure. If LNG is essentially pure methane, the storage temperature then is about 111.4 K, the normal boiling point of methane. The enormous amount of cold liquid can in principle serve as a heat sink for an onboard heat engine. Energy discarded to the LNG serves for its vaporization. If the heat source is ambient air at 300 K, and if the efficiency of a heat engine is 61% of its Carnot value, estimate the vaporization rate in moles vaporized per kJ of power output. For methane,

0.2 mol/kJ

Explanation:

Methane is stored at a temperature of 111.4K, . The heat source to vapourization of methane is ambient air which is at 300 K.

Estimate the vaporization rate at the efficiency of heat engine 60% of its carnot value.

Calculate the vaporization rate from the given data by relation shown below:

here,

is the heat at temperature is the phase transition enthalpy of methane and W is the work

Calculate from the equation shown below:

where Q_n is the  heat at temperature of and is the efficiency of heat engine

calculate from the relation shown below:

calculate the heat engine efficiency from the given carnot engine efficiency as shown below

here, is the carnot engine efficiency

substituting the values of temperature, we have

substitute values of in equation 4, we get

check the attached file for additional solution

the energy to form plasma comes from heat or electricity in the atmosphere!

sunny~ ☺