How much energy would be absorbed as heat by 75 g of iron when heated from 295 k to 301 k?

q = 202.5 joules

Explanation:

The amount of energy absorbed as one heat 75 grams of iron from 295 k to 301 k can be computed below

q = mcΔt

where

q = energy

m = mass

c = specific heat capacity

Δt = change in temperature

Δt = final temperature - initial temperature

Δt = 301 - 295 = 6 k

c = 0.45  J/g  K

q =  75 g × 0.45 J/g  K × 6 K

g cancels g and k cancels k we are left with the unit in joules

q = 202.5 joules

answer: you could do some invislibe ink.

explanation: i will tell you how to if u answer my question.

2h2o2--> 2h2o + o2

this reaction is of the spontaneous decomposition of hydrogen peroxide down into water and oxygen.

add 2 molecules of hydrogen peroxide and 2 molecules of water. since oxygen is naturally diatomic, the total number of atoms of each element is now the same on both sides of the equation so it is balanced.

this may not be entirely correct but let me know.