Match the standard reduction potentials for each half reaction and the electric potential for the voltaic cell.
Given:
half-cell:
Be
2
+
∣
Be
reduction half-reaction:
Be
2
+
+
2
e
_
→
Be
E
0
=
half-cell:
Hg
2
+
∣
Hg
reduction half-reaction:
Hg
2
+
+
2
e
_
→
Hg
E
0
=
anode:
Be
2
+
cathode:
Hg
2
+
E
cell
0
=
E
cathode
0
-
E
anode
0
E
cell
0
=
Answers: 3
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