An electron travelling at 3.7 x 105 m/s has an uncertainty in its velocity of 1.88 x 105 m/s. What is the uncertainty in its position (in pm)? (Just put the number, don't use scientific notation and decimal point in the final answer) Avogadro's number = 6.022 x 1023, h = 6.626 x 10-34 J. s, c = 3.00 x 108 m/s, me= 9.109 x 10-31 kg

The uncertainty in its position is 308 pm

Explanation:

Given;

velocity of electron, v = 3.7 x 10⁵ m/s

uncertainty in velocity of the electron, Δv =   1.88 x 10⁵ m/s

Planck's constant, h = 6.626 x 10⁻³⁴ J.s

mass of electron, m = 9.109 x 10⁻³¹ kg

Using Heisenberg's uncertainty principle, we will determine the uncertainty in the position of the electron.

Δx(mΔv) ≥ h/4π

where;

Δx is uncertainty in position

m is mass of the electron

Δv is uncertainty in velocity of the electron

h is Planck's constant

Δx

Δx = 308 x 10⁻¹² m

Δx = 308 pm

Therefore,  the uncertainty in its position is 308 pm

so here we go

atomic mass

239 + 1 = y + 134 + 3 combine like terms

240 = y + 137             subtract 137 from both terms

240 - 137 = y

103 = y

atomic number

94 = z +54 + 0

94 = z + 54               subtract 54 from both sides.

40 = z

answer

hydrocarbons are organic compounds that contain only hydrogens and carbons. they can be saturated (those which contain only carbon-carbon single bonds) or unsaturated (those which contain carbon-carbon double or triple bonds) in nature. hydrocarbons can undergo several reactions like substitution, elimination etc.  

on substituting one or more hydrogen atoms in hydrocarbon it results in the formation of haloalkane. as the halogen atoms are large compared to the carbon and hydrogen atoms, due to which the molecular weight increases and the bond become polar because of presence electronegative halogen atom and results in the increase in boiling point of the haloalkane.

thus, the correct option is (b) that is the boiling point of the new compound increases on substituting a hydrogen atom with a halogen in a hydrocarbon.