Calculate the molarity of the following solution: 2.30 moles of sodium chloride in 0.452 liters of solution.
A.1.04 M
B.5.01 M
C.0.197M

B = 5.01M

Explanation:

n= 2.3mol, V= 0.452L, C=?

Applying n= CV

2.3= C× 0.452

C= 5.08M

the number of valence electrons for each molecule or ion is shown beneath the structure. remember hydrogen will not have more than two electrons. this hydrogen is part of a covalent bond (sharing two electrons). a double bond here would cause hydrogen to share four electrons with phosphorus.