A student needs to dilute a 0.31 M Pb(NO3)2 solution to make 83.0 mL of 0.19 M Pb(NO3)2 . Set up the calculation by placing the values with the correct units into the equation. Then, calculate the volume, in milliliters, of the 0.31 M Pb(NO3)2 solution that is needed.

Answer : The volume, in milliliters, of the 0.31 M solution that needed is, 50.9 mL

Explanation :

Formula used :

where,

are the initial molarity and volume of dilute .

are the final molarity and volume of .

We are given:

Putting values in above equation, we get:

Hence, the volume, in milliliters, of the 0.31 M solution that needed is, 50.9 mL

a small container that holds a source of energy a solar cell that captures light energy and converts it into electricity a voltaic cell that uses the oxidation of a fuel to produce electricity

explanation:

the formula for the conversion of temperature from degree celsius to kelvin is:

the sample of water at is converted to kelvin temperature by using the above formula as:

on comparing the two samples of water at or we can say that at and at respectively. the difference between the temperatures of two samples of water is:

hence, one can say that the sample of water at is greater than the sample of water at by .