A wooden artifact from a Chinese temple has a 14C activity of 42.8 counts per minute as compared with an activity of 58.2 counts per minute for a standard of zero age. Part A From the half-life for 14C decay, 5715 yr, determine the age of the artifact.

Answer : The age of the artifact is,

Explanation :

Half-life = 5715 years

First we have to calculate the rate constant, we use the formula :

Now we have to calculate the time taken to decay.

Expression for rate law for first order kinetics is given by:

where,

k = rate constant

t = time taken by sample = ?

a = initial activity of the reactant  = 58.2 counts per minute

a - x = activity left after decay process  = 42.8 counts per minute

Now put all the given values in above equation, we get

Therefore, the age of the artifact is,

b. th3 n4zc4 pl4t3 15 c0nv3rg1ng w1th the s0uth 4m3ric4n pl4t3.

a electronegativity decreases beacuse the size of nucleus is bigger.