A hair straightener has a resistance of 10.0 ohms while drawing a current of 1 pe
5.0 amperes. What is the power of the straightener? *

250 Watts

Explanation:

We need to use the equation P = (I^2)*R, where P is the power in Watts, I is the current in Amperes, and R is the resistance in Ohms.

Here, we know that I = 5.0 Amperes and R = 10.0 Ohms. Plug in these values:

P = I^2 * R = (5.0)^2 * 10.0 = 250 Watts.

Hope this helps!

P= 250 Watts

Explanation:

Power is given by

P = VI

and V = IR

so

P = I * I *R or I^2R

We know I = 5 Amps and R = 10 Ohms

P = 5^2 * 10

P =25*10

P= 250 Watts

0.88m hope i am correct : )