Calculate HY3- in a solution prepared by mixing 10 ml of 0.0100 m VOSO4

Incomplete question: 9.9 mL of 0.01 M EDTA, and 10 mL of buffer with a pH of 4.

The concentration of [HY³⁻] is 1.8x10⁻²⁸mol/L

Explanation:

Given information:

10 mL of 0.01 M VOSO₄ = 0.01 L

9.9 mL of 0.01 M EDTA = 0.0099 L

10 mL of buffer = 0.01 L

pH of 4

Question: Calculate HY³⁻, [HY³⁻] = ?

Moles of EDTA:

The concentration of Y⁴⁺:

At pH = 4 Y⁴⁻ = 3.8x10⁻⁹

mol/L

The concentration of [H₂Y²⁻]:

The reaction:

H₂Y²⁻ → H⁺ + HY³⁻

The concentration of HY³⁻

Solving for HY³⁻

[HY³⁻] = 1.8x10⁻²⁸mol/L

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