What is the volume of 15.2 grams of SO2 at STP?

5.33 Liters SO₂

Explanation:

PV = nRT => V = nRT/P

n = moles SO₂ = 15.2g/64g·mol⁻¹ = 0.238 mole

R = Gas Constant = 0.08206 L·atm/mol·K

T = Kelvin Temp = 273K at STP

P = pressure in atmospheres = 1.0 atm at STP

∴ V = (0.238mol)(0.08206 L·atm/mol·K)(273K)/(1.0atm) = 5.33 Liters SO₂

the density of gold = 19.3 g/cm3

the relation between density and mass and volume is

density = mass / volume

given :

mass of gold = 13 g

density = 13g / volume = 19.3

volume = 13 /19.3 = 0.67 cm^3

thus volume of gold nugget = 0.67 cm^3

c) should be the answer.