A 3.0 L cointainer contains 4 mol He, 2 mol Ne, and 1 mol Ar. What is the mole fraction of neon gas? What is the partial pressure of Ne if the total pressure is 5 atm

Partial pressure of Ne = 1.43 atm

Explanation:

Step 1: Data given

Volume = 3.0 L

Number of moles He = 4 moles

Number of moles Ne = 2 moles

Number of moles Ar = 1 mol

Total pressure = 5 atm

Step 2: Calculate total moles

Total moles = 4 moles + 2 moles + 1 mol

Total moles = 7 moles

Step 3: Calculate the mol ratio

Mol ratio = moles / total mol

Mol ratio He = 4 moles / 7 moles = 0.571

Mol ratio Ne = 2 moles / 7 moles = 0.286

Mol ratio Ar = 1 mol / 7 moles = 0.143 moles

Ste p4: Calculate partial pressure

PArtial pressure = mol ratio * total pressure

Partial pressure of Ne = mol ratio Ne * total pressure

Partial pressure of Ne = 0.286 * 5 atm

Partial pressure of Ne = 1.43 atm

1. Mole fraction of Ne is 2/7

2. The partial pressure of Ne is 1.43 atm

Explanation:

Step 1:

Data obtained from the question. This includes:

Mole of He = 4 moles

Mole of Ne = 2 moles

Mole of Ar = 1 mole

Total mole = 7 moles

Total pressure = 5 atm

Step 2:

Determination of the mole fraction of Ne.

Mole fraction of a gas is simply the ratio of the mole of the gas to the total mole of the gas present.

Mole fraction of Ne = mol of Ne/ total mole

Mole fraction of Ne = 2/7

Step 3:

Determination of the partial pressure of Ne.

Partial pressure = mole fraction x total pressure

Partial pressure of Ne = 2/7 x 5

Partial pressure of Ne = 1.43 atm

your answer is c) plasma

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