A helium sample occupies 1.50 L of space at 124.6 kPa. What pressure would the helium need to experience to have a volume of 0.75 L?

A. 130 kPa
B. 97 kPa
C. 250 kPa
D. 62 kPa

Answer : The correct option is, (C) 250 kPa

Explanation :

Boyle's Law : It is defined as the pressure of the gas is inversely proportional to the volume of the gas at constant temperature and number of moles.

or,

where,

= initial pressure = 124.6 kPa

= final pressure = ?

= initial volume = 1.50 L

= final volume = 0.75 L

Now put all the given values in the above equation, we get:

Thus, the pressure of helium need to experience to have a volume of 0.75 L would be, 250 kPa

"among the transition metal elements, manganese and zinc have a slight lowering of electronegativities. the reason behind this is that the nuclear charges of these elements are slightly weaker than the other transition metal elements due to the way their valence electrons are filled up. both manganese and zinc have their valence electrons filled up to the 4th shell with 1 pair of electrons (4s2) completely occupying it. although the electrons in the 3rd shell (3d) are yet to be paired since the outer most shell is filled up, the ability of the nucleus to attract electrons is lessened. hence,   the electronegativity (or the ability to attract electrons) is lessened."