Sodium chloride, NaCl forms in this reaction between sodium and chlorine. 2Na(s) + Cl2(g) → 2NaCl(s) How many moles of NaCl result from the complete reaction of 3.9 mol of Cl2? Assume that there is more than enough Na.

7.8 moles of NaCl result from the complete reaction of 3.9 mol of

Explanation:

To calculate the moles :

As is the excess reagent, is the limiting reagent as it limits the formation of product.

According to stoichiometry :

1 mole of gives = 2 moles of

Thus 3.9 moles of will give=  of

7.8 moles of NaCl result from the complete reaction of 3.9 mol of

the correct answer is b. a strong acid completely dissociates to its ions when dissolved in water. completely dissociates to and ions. a is incorrect because does not fully ionize to and ions and some remain as the compound . c and d are incorrect because, and do not fall into the category of bronsted lowry acids. a bronsted lowry acid is a proton donor and since both molecules do not have a proton to donate they are not bronsted lowry acids. likewise,   if we use the lewis acid definition, they cannot be acids. a lewis acid is an electron pair acceptor. both and have a complete octet so can not accept any electrons which disqualifies them as acids.

catya your not at all which answer i've seen you do this on another question!