Given the unbalanced reaction, Fe + S > Fe S , how 8 2 3
many moles of each reactant are needed to produce 1.50 moles of iron (III) sulfide? (balance equation first)

The answer to your question is 3 moles of Fe and 4.5 moles of S

Explanation:

Data

moles of Fe = ?

moles of S = ?

moles of Fe₂S₃

Unbalanced chemical reaction

                    Fe   +  S   ⇒    Fe₂S₃

             Reactants    Elements    Products

                     1                  Fe                2

                     1                   S                 3

Balanced chemical reaction

                    2Fe   +  3S   ⇒    Fe₂S₃

             Reactants    Elements    Products

                     2                  Fe                2

                     3                   S                 3

-Calculate the moles of each reactant

                  2 moles of Fe 1 mol of Fe₂S₃

                 x                       1.5 moles Fe₂S₃

                               x = (1.5 x 2) / 1

                                x = 3 moles of Fe

-Calculate the moles of S

                  3 moles of S 1 mol of Fe₂S₃

                  x                     1.5 moles of Fe₂S₃

                                x = (1.5 x 3) / 1

                                x = 4.5 moles of S

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