A gas that has a pressure of 2 atm and
a volume of 10 L. What would be the
new volume if the pressure was
changed to 1 atm?

The answer to your question is 20 liters

Explanation:

Data

Pressure 1 = P1 = 2 atm

Volume 1 = V1 = 10 l

Pressure 2 = P2 = 1 atm

Volume 2 = V2 = ?

Process

To solve this problem use Boyle's law

              P1V1 = P2V2

-Solve for V2

              V2 = P1V1/P2

-Substitution

              V2 = (2 x 10)/1

-Simplification

              V2 = 20/1

-Result

               V2 = 20 l

in 1783 cavendish was working with his hydrogen gas and found that when he burned it and condensed the vapor it was water. this was very significant since it disproved the greek theory of elements completely since water was not a simple substance but the product of two gases. it was lavoisier who hearing of the experiment gave cavendish's gas the name hydrogen ("water-producer") and added that hydrogen burned by combining with oxygen and that water was a hydrogen-oxygen combination.

explanation: